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8.Electromagnetic waves
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Magnetic field in a plane electromagnetic wave is given by
$\vec B = {B_0}\,\sin \,\left( {kx + \omega t} \right)\hat jT$
Expression for corresponding electric field will be Where $c$ is speed of light
A
$\vec E = {B_0}\,c\sin \,\left( {kx + \omega t} \right)\hat k\,V/m$
B
$\vec E = \frac{{{B_0}}}{c}\,\sin \,\left( {kx + \omega t} \right)\hat k\,V/m$
C
$\vec E = - {B_0}\,c\sin \,\left( {kx + \omega t} \right)\hat k\,V/m$
D
$\vec E = {B_0}\,c\sin \,\left( {kx - \omega t} \right)\hat k\,V/m$
(JEE MAIN-2017)
Solution
Speed of $EM$ wave in force space $\left( c \right) = \frac{{{E_0}}}{{{B_0}}}\,$
or $\vec E = c{B_0}{\mkern 1mu} \sin {\mkern 1mu} \left( {kx + \omega t} \right)\hat k$
Standard 12
Physics
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