Magnetic field in a plane electromagnetic wave is given by 

$\vec B = {B_0}\,\sin \,\left( {kx + \omega t} \right)\hat jT$

 Expression for corresponding electric field will be Where $c$ is speed of light

  • [JEE MAIN 2017]
  • A

    $\vec E = {B_0}\,c\sin \,\left( {kx + \omega t} \right)\hat k\,V/m$

  • B

    $\vec E = \frac{{{B_0}}}{c}\,\sin \,\left( {kx + \omega t} \right)\hat k\,V/m$

  • C

    $\vec E =  - {B_0}\,c\sin \,\left( {kx + \omega t} \right)\hat k\,V/m$

  • D

    $\vec E = {B_0}\,c\sin \,\left( {kx - \omega t} \right)\hat k\,V/m$

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